-3=7(y-2)+11

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Solution for -3=7(y-2)+11 equation: 



-3=7(y-2)+11

We move all terms to the left:

-3-(7(y-2)+11)=0



We calculate terms in parentheses: -(7(y-2)+11), so:

7(y-2)+11

We multiply parentheses

7y-14+11

We add all the numbers together, and all the variables

7y-3

Back to the equation:

-(7y-3)



We get rid of parentheses

-7y+3-3=0

We add all the numbers together, and all the variables

-7y=0

y=0/-7

y=0

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