-3=k/2;k=-1

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Solution for -3=k/2;k=-1 equation:



-3=k/2k=-1
We move all terms to the left:
-3-(k/2k)=0
Domain of the equation: 2k)!=0
k!=0/1
k!=0
k∈R
We add all the numbers together, and all the variables
-(+k/2k)-3=0
We get rid of parentheses
-k/2k-3=0
We multiply all the terms by the denominator
-k-3*2k=0
We add all the numbers together, and all the variables
-1k-3*2k=0
Wy multiply elements
-1k-6k=0
We add all the numbers together, and all the variables
-7k=0
k=0/-7
k=0
Równanie nie ma rozwiązania

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