-3=m+48/10

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Solution for -3=m+48/10 equation: 



-3=m+48/10

We move all terms to the left:

-3-(m+48/10)=0

We add all the numbers together, and all the variables

-(+m+48/10)-3=0

We get rid of parentheses

-m-3-48/10=0

We multiply all the terms by the denominator


-m*10-48-3*10=0

We add all the numbers together, and all the variables

-m*10-78=0

Wy multiply elements

-10m-78=0

We move all terms containing m to the left, all other terms to the right

-10m=78

m=78/-10

m=-7+4/5

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