-3a+6(1+6a)=4(8a+1)

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Solution for -3a+6(1+6a)=4(8a+1) equation: 



-3a+6(1+6a)=4(8a+1)

We move all terms to the left:

-3a+6(1+6a)-(4(8a+1))=0

We add all the numbers together, and all the variables

-3a+6(6a+1)-(4(8a+1))=0

We multiply parentheses

-3a+36a-(4(8a+1))+6=0



We calculate terms in parentheses: -(4(8a+1)), so:

4(8a+1)

We multiply parentheses

32a+4

Back to the equation:

-(32a+4)



We add all the numbers together, and all the variables

33a-(32a+4)+6=0

We get rid of parentheses

33a-32a-4+6=0

We add all the numbers together, and all the variables

a+2=0

We move all terms containing a to the left, all other terms to the right

a=-2

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