-3a-5(3a+3)=-3(a-3)-3a

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Solution for -3a-5(3a+3)=-3(a-3)-3a equation:



-3a-5(3a+3)=-3(a-3)-3a
We move all terms to the left:
-3a-5(3a+3)-(-3(a-3)-3a)=0
We multiply parentheses
-3a-15a-(-3(a-3)-3a)-15=0
We calculate terms in parentheses: -(-3(a-3)-3a), so:
-3(a-3)-3a
We add all the numbers together, and all the variables
-3a-3(a-3)
We multiply parentheses
-3a-3a+9
We add all the numbers together, and all the variables
-6a+9
Back to the equation:
-(-6a+9)
We add all the numbers together, and all the variables
-18a-(-6a+9)-15=0
We get rid of parentheses
-18a+6a-9-15=0
We add all the numbers together, and all the variables
-12a-24=0
We move all terms containing a to the left, all other terms to the right
-12a=24
a=24/-12
a=-2

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