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-3a=5-3(a+5)
We move all terms to the left:
-3a-(5-3(a+5))=0
We calculate terms in parentheses: -(5-3(a+5)), so:We get rid of parentheses
5-3(a+5)
determiningTheFunctionDomain -3(a+5)+5
We multiply parentheses
-3a-15+5
We add all the numbers together, and all the variables
-3a-10
Back to the equation:
-(-3a-10)
-3a+3a+10=0
We add all the numbers together, and all the variables
10!=0
There is no solution for this equation
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