-3b(b-8)-5=9(b+2)-11

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Solution for -3b(b-8)-5=9(b+2)-11 equation:


Simplifying
-3b(b + -8) + -5 = 9(b + 2) + -11

Reorder the terms:
-3b(-8 + b) + -5 = 9(b + 2) + -11
(-8 * -3b + b * -3b) + -5 = 9(b + 2) + -11
(24b + -3b2) + -5 = 9(b + 2) + -11

Reorder the terms:
-5 + 24b + -3b2 = 9(b + 2) + -11

Reorder the terms:
-5 + 24b + -3b2 = 9(2 + b) + -11
-5 + 24b + -3b2 = (2 * 9 + b * 9) + -11
-5 + 24b + -3b2 = (18 + 9b) + -11

Reorder the terms:
-5 + 24b + -3b2 = 18 + -11 + 9b

Combine like terms: 18 + -11 = 7
-5 + 24b + -3b2 = 7 + 9b

Solving
-5 + 24b + -3b2 = 7 + 9b

Solving for variable 'b'.

Reorder the terms:
-5 + -7 + 24b + -9b + -3b2 = 7 + 9b + -7 + -9b

Combine like terms: -5 + -7 = -12
-12 + 24b + -9b + -3b2 = 7 + 9b + -7 + -9b

Combine like terms: 24b + -9b = 15b
-12 + 15b + -3b2 = 7 + 9b + -7 + -9b

Reorder the terms:
-12 + 15b + -3b2 = 7 + -7 + 9b + -9b

Combine like terms: 7 + -7 = 0
-12 + 15b + -3b2 = 0 + 9b + -9b
-12 + 15b + -3b2 = 9b + -9b

Combine like terms: 9b + -9b = 0
-12 + 15b + -3b2 = 0

Factor out the Greatest Common Factor (GCF), '3'.
3(-4 + 5b + -1b2) = 0

Factor a trinomial.
3((-4 + b)(1 + -1b)) = 0

Ignore the factor 3.

Subproblem 1

Set the factor '(-4 + b)' equal to zero and attempt to solve: Simplifying -4 + b = 0 Solving -4 + b = 0 Move all terms containing b to the left, all other terms to the right. Add '4' to each side of the equation. -4 + 4 + b = 0 + 4 Combine like terms: -4 + 4 = 0 0 + b = 0 + 4 b = 0 + 4 Combine like terms: 0 + 4 = 4 b = 4 Simplifying b = 4

Subproblem 2

Set the factor '(1 + -1b)' equal to zero and attempt to solve: Simplifying 1 + -1b = 0 Solving 1 + -1b = 0 Move all terms containing b to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1b = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1b = 0 + -1 -1b = 0 + -1 Combine like terms: 0 + -1 = -1 -1b = -1 Divide each side by '-1'. b = 1 Simplifying b = 1

Solution

b = {4, 1}

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