-3b+4(1+2b)=-23-4b=

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Solution for -3b+4(1+2b)=-23-4b= equation: 



-3b+4(1+2b)=-23-4b=

We move all terms to the left:

-3b+4(1+2b)-(-23-4b)=0

We add all the numbers together, and all the variables

-3b+4(2b+1)-(-4b-23)=0

We multiply parentheses

-3b+8b-(-4b-23)+4=0

We get rid of parentheses

-3b+8b+4b+23+4=0

We add all the numbers together, and all the variables

9b+27=0

We move all terms containing b to the left, all other terms to the right

9b=-27

b=-27/9

b=-3

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