-3b+5(b+2)=4-(3b+5)

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Solution for -3b+5(b+2)=4-(3b+5) equation: 



-3b+5(b+2)=4-(3b+5)

We move all terms to the left:

-3b+5(b+2)-(4-(3b+5))=0

We multiply parentheses

-3b+5b-(4-(3b+5))+10=0



We calculate terms in parentheses: -(4-(3b+5)), so:

4-(3b+5)

determiningTheFunctionDomain
-(3b+5)+4

We get rid of parentheses

-3b-5+4

We add all the numbers together, and all the variables

-3b-1

Back to the equation:

-(-3b-1)



We add all the numbers together, and all the variables

2b-(-3b-1)+10=0

We get rid of parentheses

2b+3b+1+10=0

We add all the numbers together, and all the variables

5b+11=0

We move all terms containing b to the left, all other terms to the right

5b=-11

b=-11/5

b=-2+1/5

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