-3b+5(b+4)+4(b+3)=2

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Solution for -3b+5(b+4)+4(b+3)=2 equation:


-3b+5(b+4)+4(b+3)=2

We simplify the equation to the form, which is simple to understand
-3b+5(b+4)+4(b+3)=2

Reorder the terms in parentheses
-3b+(+5b+20)+4*(b+3)=2

Remove unnecessary parentheses
-3b+5b+20+4+*(+b+3+)=+2

Reorder the terms in parentheses
-3b+5b+20+(+4b+12)=2

Remove unnecessary parentheses
-3b+5b+20+4b+12=+2

We move all terms containing b to the left and all other terms to the right.
-3b+5b+4b=+2-20-12

We simplify left and right side of the equation.
+6b=-30

We divide both sides of the equation by 6 to get b.
b=-5

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