-3b-11=5+2(b+2)

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Solution for -3b-11=5+2(b+2) equation: 



-3b-11=5+2(b+2)

We move all terms to the left:

-3b-11-(5+2(b+2))=0



We calculate terms in parentheses: -(5+2(b+2)), so:

5+2(b+2)

determiningTheFunctionDomain
2(b+2)+5

We multiply parentheses

2b+4+5

We add all the numbers together, and all the variables

2b+9

Back to the equation:

-(2b+9)



We get rid of parentheses

-3b-2b-9-11=0

We add all the numbers together, and all the variables

-5b-20=0

We move all terms containing b to the left, all other terms to the right

-5b=20

b=20/-5

b=-4

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