-3b-12+4b=3b-12-2b

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Solution for -3b-12+4b=3b-12-2b equation: 



-3b-12+4b=3b-12-2b

We move all terms to the left:

-3b-12+4b-(3b-12-2b)=0

We add all the numbers together, and all the variables

-3b+4b-(b-12)-12=0

We add all the numbers together, and all the variables

b-(b-12)-12=0

We get rid of parentheses

b-b+12-12=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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