-3b-12+4b=3b-12-2b

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Solution for -3b-12+4b=3b-12-2b equation:



-3b-12+4b=3b-12-2b
We move all terms to the left:
-3b-12+4b-(3b-12-2b)=0
We add all the numbers together, and all the variables
-3b+4b-(b-12)-12=0
We add all the numbers together, and all the variables
b-(b-12)-12=0
We get rid of parentheses
b-b+12-12=0
We add all the numbers together, and all the variables
=0
b=0/1
b=0

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