-3c+4+5c=1/2(6-8c)

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Solution for -3c+4+5c=1/2(6-8c) equation: 



-3c+4+5c=1/2(6-8c)

We move all terms to the left:

-3c+4+5c-(1/2(6-8c))=0



Domain of the equation: 2(6-8c))!=0

c∈R



We add all the numbers together, and all the variables

-3c+5c-(1/2(-8c+6))+4=0

We add all the numbers together, and all the variables

2c-(1/2(-8c+6))+4=0

We multiply all the terms by the denominator


2c*2(-8c+6))-(1+4*2(-8c+6))=0

Wy multiply elements

4c^2(-+8c(-=0

We use the square of the difference formula

4c^2(-8c(-=0

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