-3c+5(c+3)=23

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Solution for -3c+5(c+3)=23 equation: 



-3c+5(c+3)=23

We move all terms to the left:

-3c+5(c+3)-(23)=0

We multiply parentheses

-3c+5c+15-23=0

We add all the numbers together, and all the variables

2c-8=0

We move all terms containing c to the left, all other terms to the right

2c=8

c=8/2

c=4

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