-3c+d=12;4c-5d=-27

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Solution for -3c+d=12;4c-5d=-27 system of equations: 


  • /| d-3*c-12 = 0| 4*c-(5*d)+27 = 0
  • We try to solve the equation: d-3*c-12 = 0
  • d-3*c-12 = 0 // + -3*c-12
  • d = -(-3*c-12)
  • d = 12-(-3*c)
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| 4*c-(5*(12-(-3*c)))+27 = 0| d = 12-(-3*c)
  • 4*c-1*5*(3*c+12)+27 = 0
  • 27-11*c-60 = 0
  • -11*c-33 = 0
  • -11*c-33 = 0 // + 33
  • -11*c = 33 // : -11
  • c = 33/(-11)
  • c = -3
  • We insert the solution into one of the initial equations of our system of equations
  • For d = 12-(-3*c): 
  • d = 12-(-3*(-3))
  • d = 12-(3*3)
  • d = 12-9
  • d = 3
  • We get a system of equations:
  • /| d = 3| c = -3

 

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