-3f(6f-12)=36-18f

Solution for -3f(6f-12)=36-18f equation:

-3f(6f-12)=36-18f

We move all terms to the left:

-3f(6f-12)-(36-18f)=0

We add all the numbers together, and all the variables

-3f(6f-12)-(-18f+36)=0

We multiply parentheses

-18f^2+36f-(-18f+36)=0

We get rid of parentheses

-18f^2+36f+18f-36=0

We add all the numbers together, and all the variables

-18f^2+54f-36=0

a = -18; b = 54; c = -36;
Δ = b2-4ac
Δ = 542-4·(-18)·(-36)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(54)-18}{2*-18}=\frac{-72}{-36}
=+2
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(54)+18}{2*-18}=\frac{-36}{-36}
=1
$