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-3h(h-6)=5(2h+3)
We move all terms to the left:
-3h(h-6)-(5(2h+3))=0
We multiply parentheses
-3h^2+18h-(5(2h+3))=0
We calculate terms in parentheses: -(5(2h+3)), so:We get rid of parentheses
5(2h+3)
We multiply parentheses
10h+15
Back to the equation:
-(10h+15)
-3h^2+18h-10h-15=0
We add all the numbers together, and all the variables
-3h^2+8h-15=0
a = -3; b = 8; c = -15;
Δ = b2-4ac
Δ = 82-4·(-3)·(-15)
Δ = -116
Delta is less than zero, so there is no solution for the equation
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