-3j-10=2(j-10)

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Solution for -3j-10=2(j-10) equation: 



-3j-10=2(j-10)

We move all terms to the left:

-3j-10-(2(j-10))=0



We calculate terms in parentheses: -(2(j-10)), so:

2(j-10)

We multiply parentheses

2j-20

Back to the equation:

-(2j-20)



We get rid of parentheses

-3j-2j+20-10=0

We add all the numbers together, and all the variables

-5j+10=0

We move all terms containing j to the left, all other terms to the right

-5j=-10

j=-10/-5

j=+2

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