-3k-3(2k-2)=33

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Solution for -3k-3(2k-2)=33 equation: 



-3k-3(2k-2)=33

We move all terms to the left:

-3k-3(2k-2)-(33)=0

We multiply parentheses

-3k-6k+6-33=0

We add all the numbers together, and all the variables

-9k-27=0

We move all terms containing k to the left, all other terms to the right

-9k=27

k=27/-9

k=-3

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