-3m(4+m)=-36

Solution for -3m(4+m)=-36 equation:

-3m(4+m)=-36

We move all terms to the left:

-3m(4+m)-(-36)=0

We add all the numbers together, and all the variables

-3m(m+4)-(-36)=0

We add all the numbers together, and all the variables

-3m(m+4)+36=0

We multiply parentheses

-3m^2-12m+36=0

a = -3; b = -12; c = +36;
Δ = b2-4ac
Δ = -122-4·(-3)·36
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-24}{2*-3}=\frac{-12}{-6}
=+2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+24}{2*-3}=\frac{36}{-6}
=-6
$