-3m+2(m-1)=3(4-m)-2m

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Solution for -3m+2(m-1)=3(4-m)-2m equation: 



-3m+2(m-1)=3(4-m)-2m

We move all terms to the left:

-3m+2(m-1)-(3(4-m)-2m)=0

We add all the numbers together, and all the variables

-3m+2(m-1)-(3(-1m+4)-2m)=0

We multiply parentheses

-3m+2m-(3(-1m+4)-2m)-2=0



We calculate terms in parentheses: -(3(-1m+4)-2m), so:

3(-1m+4)-2m

We add all the numbers together, and all the variables

-2m+3(-1m+4)

We multiply parentheses

-2m-3m+12

We add all the numbers together, and all the variables

-5m+12

Back to the equation:

-(-5m+12)



We add all the numbers together, and all the variables

-1m-(-5m+12)-2=0

We get rid of parentheses

-1m+5m-12-2=0

We add all the numbers together, and all the variables

4m-14=0

We move all terms containing m to the left, all other terms to the right

4m=14

m=14/4

m=3+1/2

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