-3m-7-4(m-2)=6m-(9m-4)+7m+6

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Solution for -3m-7-4(m-2)=6m-(9m-4)+7m+6 equation: 



-3m-7-4(m-2)=6m-(9m-4)+7m+6

We move all terms to the left:

-3m-7-4(m-2)-(6m-(9m-4)+7m+6)=0

We multiply parentheses

-3m-4m-(6m-(9m-4)+7m+6)+8-7=0



We calculate terms in parentheses: -(6m-(9m-4)+7m+6), so:

6m-(9m-4)+7m+6

We add all the numbers together, and all the variables

13m-(9m-4)+6

We get rid of parentheses

13m-9m+4+6

We add all the numbers together, and all the variables

4m+10

Back to the equation:

-(4m+10)



We add all the numbers together, and all the variables

-7m-(4m+10)+1=0

We get rid of parentheses

-7m-4m-10+1=0

We add all the numbers together, and all the variables

-11m-9=0

We move all terms containing m to the left, all other terms to the right

-11m=9

m=9/-11

m=-9/11

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