-3n-2(n+3)=-4(n+1)

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Solution for -3n-2(n+3)=-4(n+1) equation: 



-3n-2(n+3)=-4(n+1)

We move all terms to the left:

-3n-2(n+3)-(-4(n+1))=0

We multiply parentheses

-3n-2n-(-4(n+1))-6=0



We calculate terms in parentheses: -(-4(n+1)), so:

-4(n+1)

We multiply parentheses

-4n-4

Back to the equation:

-(-4n-4)



We add all the numbers together, and all the variables

-5n-(-4n-4)-6=0

We get rid of parentheses

-5n+4n+4-6=0

We add all the numbers together, and all the variables

-1n-2=0

We move all terms containing n to the left, all other terms to the right

-n=2

n=2/-1

n=-2

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