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-3p^2+7p=1
We move all terms to the left:
-3p^2+7p-(1)=0
a = -3; b = 7; c = -1;
Δ = b2-4ac
Δ = 72-4·(-3)·(-1)
Δ = 37
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{37}}{2*-3}=\frac{-7-\sqrt{37}}{-6} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{37}}{2*-3}=\frac{-7+\sqrt{37}}{-6} $
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