-3r+19=3(4-r)+3

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Solution for -3r+19=3(4-r)+3 equation: 



-3r+19=3(4-r)+3

We move all terms to the left:

-3r+19-(3(4-r)+3)=0

We add all the numbers together, and all the variables

-3r-(3(-1r+4)+3)+19=0



We calculate terms in parentheses: -(3(-1r+4)+3), so:

3(-1r+4)+3

We multiply parentheses

-3r+12+3

We add all the numbers together, and all the variables

-3r+15

Back to the equation:

-(-3r+15)



We get rid of parentheses

-3r+3r-15+19=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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