-3r+2(-6r-5)=-7(r-2)

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Solution for -3r+2(-6r-5)=-7(r-2) equation: 



-3r+2(-6r-5)=-7(r-2)

We move all terms to the left:

-3r+2(-6r-5)-(-7(r-2))=0

We multiply parentheses

-3r-12r-(-7(r-2))-10=0



We calculate terms in parentheses: -(-7(r-2)), so:

-7(r-2)

We multiply parentheses

-7r+14

Back to the equation:

-(-7r+14)



We add all the numbers together, and all the variables

-15r-(-7r+14)-10=0

We get rid of parentheses

-15r+7r-14-10=0

We add all the numbers together, and all the variables

-8r-24=0

We move all terms containing r to the left, all other terms to the right

-8r=24

r=24/-8

r=-3

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