-3r+3(r-2)=-2(r+6)

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Solution for -3r+3(r-2)=-2(r+6) equation: 



-3r+3(r-2)=-2(r+6)

We move all terms to the left:

-3r+3(r-2)-(-2(r+6))=0

We multiply parentheses

-3r+3r-(-2(r+6))-6=0



We calculate terms in parentheses: -(-2(r+6)), so:

-2(r+6)

We multiply parentheses

-2r-12

Back to the equation:

-(-2r-12)



We add all the numbers together, and all the variables

-(-2r-12)-6=0

We get rid of parentheses

2r+12-6=0

We add all the numbers together, and all the variables

2r+6=0

We move all terms containing r to the left, all other terms to the right

2r=-6

r=-6/2

r=-3

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