-3r+5(3-2r)=106

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Solution for -3r+5(3-2r)=106 equation: 



-3r+5(3-2r)=106

We move all terms to the left:

-3r+5(3-2r)-(106)=0

We add all the numbers together, and all the variables

-3r+5(-2r+3)-106=0

We multiply parentheses

-3r-10r+15-106=0

We add all the numbers together, and all the variables

-13r-91=0

We move all terms containing r to the left, all other terms to the right

-13r=91

r=91/-13

r=-7

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