-3r+5(3-2r)=106

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Solution for -3r+5(3-2r)=106 equation:



-3r+5(3-2r)=106
We move all terms to the left:
-3r+5(3-2r)-(106)=0
We add all the numbers together, and all the variables
-3r+5(-2r+3)-106=0
We multiply parentheses
-3r-10r+15-106=0
We add all the numbers together, and all the variables
-13r-91=0
We move all terms containing r to the left, all other terms to the right
-13r=91
r=91/-13
r=-7

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