-3t2=-108

Solution for -3t2=-108 equation:

-3t^2=-108

We move all terms to the left:

-3t^2-(-108)=0

We add all the numbers together, and all the variables

-3t^2+108=0

a = -3; b = 0; c = +108;
Δ = b2-4ac
Δ = 02-4·(-3)·108
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*-3}=\frac{-36}{-6}
=+6
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*-3}=\frac{36}{-6}
=-6
$