-3v+6v=3(8-2v)-5(1+2v)

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Solution for -3v+6v=3(8-2v)-5(1+2v) equation: 



-3v+6v=3(8-2v)-5(1+2v)

We move all terms to the left:

-3v+6v-(3(8-2v)-5(1+2v))=0

We add all the numbers together, and all the variables

-3v+6v-(3(-2v+8)-5(2v+1))=0

We add all the numbers together, and all the variables

3v-(3(-2v+8)-5(2v+1))=0



We calculate terms in parentheses: -(3(-2v+8)-5(2v+1)), so:

3(-2v+8)-5(2v+1)

We multiply parentheses

-6v-10v+24-5

We add all the numbers together, and all the variables

-16v+19

Back to the equation:

-(-16v+19)



We get rid of parentheses

3v+16v-19=0

We add all the numbers together, and all the variables

19v-19=0

We move all terms containing v to the left, all other terms to the right

19v=19

v=19/19

v=1

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