-3v-5(v-8)=7(12-8v)+4v

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Solution for -3v-5(v-8)=7(12-8v)+4v equation: 



-3v-5(v-8)=7(12-8v)+4v

We move all terms to the left:

-3v-5(v-8)-(7(12-8v)+4v)=0

We add all the numbers together, and all the variables

-3v-5(v-8)-(7(-8v+12)+4v)=0

We multiply parentheses

-3v-5v-(7(-8v+12)+4v)+40=0



We calculate terms in parentheses: -(7(-8v+12)+4v), so:

7(-8v+12)+4v

We add all the numbers together, and all the variables

4v+7(-8v+12)

We multiply parentheses

4v-56v+84

We add all the numbers together, and all the variables

-52v+84

Back to the equation:

-(-52v+84)



We add all the numbers together, and all the variables

-8v-(-52v+84)+40=0

We get rid of parentheses

-8v+52v-84+40=0

We add all the numbers together, and all the variables

44v-44=0

We move all terms containing v to the left, all other terms to the right

44v=44

v=44/44

v=1

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