-3w(w+4)=4w-5

Solution for -3w(w+4)=4w-5 equation:

-3w(w+4)=4w-5

We move all terms to the left:

-3w(w+4)-(4w-5)=0

We multiply parentheses

-3w^2-12w-(4w-5)=0

We get rid of parentheses

-3w^2-12w-4w+5=0

We add all the numbers together, and all the variables

-3w^2-16w+5=0

a = -3; b = -16; c = +5;
Δ = b2-4ac
Δ = -162-4·(-3)·5
Δ = 316
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{316}=\sqrt{4*79}=\sqrt{4}*\sqrt{79}=2\sqrt{79}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-2\sqrt{79}}{2*-3}=\frac{16-2\sqrt{79}}{-6}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+2\sqrt{79}}{2*-3}=\frac{16+2\sqrt{79}}{-6}
$