-3x(-4-2x)=-2(x-1)

Solution for -3x(-4-2x)=-2(x-1) equation:

-3x(-4-2x)=-2(x-1)

We move all terms to the left:

-3x(-4-2x)-(-2(x-1))=0

We add all the numbers together, and all the variables

-3x(-2x-4)-(-2(x-1))=0

We multiply parentheses

6x^2+12x-(-2(x-1))=0


We calculate terms in parentheses: -(-2(x-1)), so:

-2(x-1)

We multiply parentheses

-2x+2

Back to the equation:

-(-2x+2)


We get rid of parentheses

6x^2+12x+2x-2=0

We add all the numbers together, and all the variables

6x^2+14x-2=0

a = 6; b = 14; c = -2;
Δ = b2-4ac
Δ = 142-4·6·(-2)
Δ = 244
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{244}=\sqrt{4*61}=\sqrt{4}*\sqrt{61}=2\sqrt{61}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-2\sqrt{61}}{2*6}=\frac{-14-2\sqrt{61}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+2\sqrt{61}}{2*6}=\frac{-14+2\sqrt{61}}{12}
$