-3x(-4-2x)=-2+x-1)

Solution for -3x(-4-2x)=-2+x-1) equation:

-3x(-4-2x)=-2+x-1)

We move all terms to the left:

-3x(-4-2x)-(-2+x-1))=0

We add all the numbers together, and all the variables

-3x(-2x-4)-(x-3))=0

We multiply parentheses

6x^2+12x-(x-3))=0

We get rid of parentheses

6x^2+12x-x+3)=0

We add all the numbers together, and all the variables

6x^2+11x=0

a = 6; b = 11; c = 0;
Δ = b2-4ac
Δ = 112-4·6·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-11}{2*6}=\frac{-22}{12}
=-1+5/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+11}{2*6}=\frac{0}{12}
=0
$