-3x(10x+12)=-12(12x+3)

Solution for -3x(10x+12)=-12(12x+3) equation:

-3x(10x+12)=-12(12x+3)

We move all terms to the left:

-3x(10x+12)-(-12(12x+3))=0

We multiply parentheses

-30x^2-36x-(-12(12x+3))=0


We calculate terms in parentheses: -(-12(12x+3)), so:

-12(12x+3)

We multiply parentheses

-144x-36

Back to the equation:

-(-144x-36)


We get rid of parentheses

-30x^2-36x+144x+36=0

We add all the numbers together, and all the variables

-30x^2+108x+36=0

a = -30; b = 108; c = +36;
Δ = b2-4ac
Δ = 1082-4·(-30)·36
Δ = 15984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{15984}=\sqrt{144*111}=\sqrt{144}*\sqrt{111}=12\sqrt{111}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(108)-12\sqrt{111}}{2*-30}=\frac{-108-12\sqrt{111}}{-60}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(108)+12\sqrt{111}}{2*-30}=\frac{-108+12\sqrt{111}}{-60}
$