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-3x(10x+12)=-12(12x+3)
We move all terms to the left:
-3x(10x+12)-(-12(12x+3))=0
We multiply parentheses
-30x^2-36x-(-12(12x+3))=0
We calculate terms in parentheses: -(-12(12x+3)), so:We get rid of parentheses
-12(12x+3)
We multiply parentheses
-144x-36
Back to the equation:
-(-144x-36)
-30x^2-36x+144x+36=0
We add all the numbers together, and all the variables
-30x^2+108x+36=0
a = -30; b = 108; c = +36;
Δ = b2-4ac
Δ = 1082-4·(-30)·36
Δ = 15984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{15984}=\sqrt{144*111}=\sqrt{144}*\sqrt{111}=12\sqrt{111}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(108)-12\sqrt{111}}{2*-30}=\frac{-108-12\sqrt{111}}{-60} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(108)+12\sqrt{111}}{2*-30}=\frac{-108+12\sqrt{111}}{-60} $
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