-3x(2x-5)-23x=12+7(-3x+5)

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Solution for -3x(2x-5)-23x=12+7(-3x+5) equation: 



-3x(2x-5)-23x=12+7(-3x+5)

We move all terms to the left:

-3x(2x-5)-23x-(12+7(-3x+5))=0

We add all the numbers together, and all the variables

-23x-3x(2x-5)-(12+7(-3x+5))=0

We multiply parentheses

-6x^2-23x+15x-(12+7(-3x+5))=0



We calculate terms in parentheses: -(12+7(-3x+5)), so:

12+7(-3x+5)

determiningTheFunctionDomain
7(-3x+5)+12

We multiply parentheses

-21x+35+12

We add all the numbers together, and all the variables

-21x+47

Back to the equation:

-(-21x+47)



We add all the numbers together, and all the variables

-6x^2-8x-(-21x+47)=0

We get rid of parentheses

-6x^2-8x+21x-47=0

We add all the numbers together, and all the variables

-6x^2+13x-47=0

a = -6; b = 13; c = -47;
Δ = b2-4ac
Δ = 132-4·(-6)·(-47)
Δ = -959
Delta is less than zero, so there is no solution for the equation

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