-3x(40-29)=8(x+5)=5x-7

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Solution for -3x(40-29)=8(x+5)=5x-7 equation: 



-3x(40-29)=8(x+5)=5x-7

We move all terms to the left:

-3x(40-29)-(8(x+5))=0

We add all the numbers together, and all the variables

-3x11-(8(x+5))=0

We add all the numbers together, and all the variables

-3x^11-(8(x+5))=0



We calculate terms in parentheses: -(8(x+5)), so:

8(x+5)

We multiply parentheses

8x+40

Back to the equation:

-(8x+40)



We do not support expression: x^11

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