-3x(4x-2)=-12x-2

Solution for -3x(4x-2)=-12x-2 equation:

-3x(4x-2)=-12x-2

We move all terms to the left:

-3x(4x-2)-(-12x-2)=0

We multiply parentheses

-12x^2+6x-(-12x-2)=0

We get rid of parentheses

-12x^2+6x+12x+2=0

We add all the numbers together, and all the variables

-12x^2+18x+2=0

a = -12; b = 18; c = +2;
Δ = b2-4ac
Δ = 182-4·(-12)·2
Δ = 420
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{420}=\sqrt{4*105}=\sqrt{4}*\sqrt{105}=2\sqrt{105}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{105}}{2*-12}=\frac{-18-2\sqrt{105}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{105}}{2*-12}=\frac{-18+2\sqrt{105}}{-24}
$