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-3x(x+3)=-6(x-3)
We move all terms to the left:
-3x(x+3)-(-6(x-3))=0
We multiply parentheses
-3x^2-9x-(-6(x-3))=0
We calculate terms in parentheses: -(-6(x-3)), so:We get rid of parentheses
-6(x-3)
We multiply parentheses
-6x+18
Back to the equation:
-(-6x+18)
-3x^2-9x+6x-18=0
We add all the numbers together, and all the variables
-3x^2-3x-18=0
a = -3; b = -3; c = -18;
Δ = b2-4ac
Δ = -32-4·(-3)·(-18)
Δ = -207
Delta is less than zero, so there is no solution for the equation
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