-3x(x+8)+6(x+1)=8+10x+2

Solution for -3x(x+8)+6(x+1)=8+10x+2 equation:

-3x(x+8)+6(x+1)=8+10x+2

We move all terms to the left:

-3x(x+8)+6(x+1)-(8+10x+2)=0

We add all the numbers together, and all the variables

-3x(x+8)+6(x+1)-(10x+10)=0

We multiply parentheses

-3x^2-24x+6x-(10x+10)+6=0

We get rid of parentheses

-3x^2-24x+6x-10x-10+6=0

We add all the numbers together, and all the variables

-3x^2-28x-4=0

a = -3; b = -28; c = -4;
Δ = b2-4ac
Δ = -282-4·(-3)·(-4)
Δ = 736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{736}=\sqrt{16*46}=\sqrt{16}*\sqrt{46}=4\sqrt{46}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-4\sqrt{46}}{2*-3}=\frac{28-4\sqrt{46}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+4\sqrt{46}}{2*-3}=\frac{28+4\sqrt{46}}{-6}
$