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-3x(x+8)-x=12
We move all terms to the left:
-3x(x+8)-x-(12)=0
We add all the numbers together, and all the variables
-1x-3x(x+8)-12=0
We multiply parentheses
-3x^2-1x-24x-12=0
We add all the numbers together, and all the variables
-3x^2-25x-12=0
a = -3; b = -25; c = -12;
Δ = b2-4ac
Δ = -252-4·(-3)·(-12)
Δ = 481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-\sqrt{481}}{2*-3}=\frac{25-\sqrt{481}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+\sqrt{481}}{2*-3}=\frac{25+\sqrt{481}}{-6} $
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