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-3x(x-4)=-x+8
We move all terms to the left:
-3x(x-4)-(-x+8)=0
We add all the numbers together, and all the variables
-3x(x-4)-(-1x+8)=0
We multiply parentheses
-3x^2+12x-(-1x+8)=0
We get rid of parentheses
-3x^2+12x+1x-8=0
We add all the numbers together, and all the variables
-3x^2+13x-8=0
a = -3; b = 13; c = -8;
Δ = b2-4ac
Δ = 132-4·(-3)·(-8)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(13)-\sqrt{73}}{2*-3}=\frac{-13-\sqrt{73}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(13)+\sqrt{73}}{2*-3}=\frac{-13+\sqrt{73}}{-6} $
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