-3x(x-4)=12

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Solution for -3x(x-4)=12 equation: 



-3x(x-4)=12

We move all terms to the left:

-3x(x-4)-(12)=0

We multiply parentheses

-3x^2+12x-12=0

a = -3; b = 12; c = -12;
Δ = b2-4ac
Δ = 122-4·(-3)·(-12)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-12}{-6}=+2$

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