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-3x(x-8)=24
We move all terms to the left:
-3x(x-8)-(24)=0
We multiply parentheses
-3x^2+24x-24=0
a = -3; b = 24; c = -24;
Δ = b2-4ac
Δ = 242-4·(-3)·(-24)
Δ = 288
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{288}=\sqrt{144*2}=\sqrt{144}*\sqrt{2}=12\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-12\sqrt{2}}{2*-3}=\frac{-24-12\sqrt{2}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+12\sqrt{2}}{2*-3}=\frac{-24+12\sqrt{2}}{-6} $
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