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-3x(x-9)=5x-3(x+2)
We move all terms to the left:
-3x(x-9)-(5x-3(x+2))=0
We multiply parentheses
-3x^2+27x-(5x-3(x+2))=0
We calculate terms in parentheses: -(5x-3(x+2)), so:We get rid of parentheses
5x-3(x+2)
We multiply parentheses
5x-3x-6
We add all the numbers together, and all the variables
2x-6
Back to the equation:
-(2x-6)
-3x^2+27x-2x+6=0
We add all the numbers together, and all the variables
-3x^2+25x+6=0
a = -3; b = 25; c = +6;
Δ = b2-4ac
Δ = 252-4·(-3)·6
Δ = 697
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-\sqrt{697}}{2*-3}=\frac{-25-\sqrt{697}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+\sqrt{697}}{2*-3}=\frac{-25+\sqrt{697}}{-6} $
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