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-3x(5+-3/x)=51
We move all terms to the left:
-3x(5+-3/x)-(51)=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-3x(-3/x)-51=0
We multiply parentheses
9x^2-51=0
a = 9; b = 0; c = -51;
Δ = b2-4ac
Δ = 02-4·9·(-51)
Δ = 1836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1836}=\sqrt{36*51}=\sqrt{36}*\sqrt{51}=6\sqrt{51}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{51}}{2*9}=\frac{0-6\sqrt{51}}{18} =-\frac{6\sqrt{51}}{18} =-\frac{\sqrt{51}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{51}}{2*9}=\frac{0+6\sqrt{51}}{18} =\frac{6\sqrt{51}}{18} =\frac{\sqrt{51}}{3} $
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