-3x+(2x-5)=-4-3(2x+4)+3x

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Solution for -3x+(2x-5)=-4-3(2x+4)+3x equation: 



-3x+(2x-5)=-4-3(2x+4)+3x

We move all terms to the left:

-3x+(2x-5)-(-4-3(2x+4)+3x)=0

We get rid of parentheses

-3x+2x-(-4-3(2x+4)+3x)-5=0



We calculate terms in parentheses: -(-4-3(2x+4)+3x), so:

-4-3(2x+4)+3x

determiningTheFunctionDomain
-3(2x+4)+3x-4

We add all the numbers together, and all the variables

3x-3(2x+4)-4

We multiply parentheses

3x-6x-12-4

We add all the numbers together, and all the variables

-3x-16

Back to the equation:

-(-3x-16)



We add all the numbers together, and all the variables

-1x-(-3x-16)-5=0

We get rid of parentheses

-1x+3x+16-5=0

We add all the numbers together, and all the variables

2x+11=0

We move all terms containing x to the left, all other terms to the right

2x=-11

x=-11/2

x=-5+1/2

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