-3x+2(5x-4)=4(20-X)

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Solution for -3x+2(5x-4)=4(20-X) equation:



-3x+2(5x-4)=4(20-x)
We move all terms to the left:
-3x+2(5x-4)-(4(20-x))=0
We add all the numbers together, and all the variables
-3x+2(5x-4)-(4(-1x+20))=0
We multiply parentheses
-3x+10x-(4(-1x+20))-8=0
We calculate terms in parentheses: -(4(-1x+20)), so:
4(-1x+20)
We multiply parentheses
-4x+80
Back to the equation:
-(-4x+80)
We add all the numbers together, and all the variables
7x-(-4x+80)-8=0
We get rid of parentheses
7x+4x-80-8=0
We add all the numbers together, and all the variables
11x-88=0
We move all terms containing x to the left, all other terms to the right
11x=88
x=88/11
x=8

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