-3x+2(5x-4)=4(20-X)

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Solution for -3x+2(5x-4)=4(20-X) equation: 



-3x+2(5x-4)=4(20-x)

We move all terms to the left:

-3x+2(5x-4)-(4(20-x))=0

We add all the numbers together, and all the variables

-3x+2(5x-4)-(4(-1x+20))=0

We multiply parentheses

-3x+10x-(4(-1x+20))-8=0



We calculate terms in parentheses: -(4(-1x+20)), so:

4(-1x+20)

We multiply parentheses

-4x+80

Back to the equation:

-(-4x+80)



We add all the numbers together, and all the variables

7x-(-4x+80)-8=0

We get rid of parentheses

7x+4x-80-8=0

We add all the numbers together, and all the variables

11x-88=0

We move all terms containing x to the left, all other terms to the right

11x=88

x=88/11

x=8

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