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-3x+2(8x-4)=2(3x+2)+x
We move all terms to the left:
-3x+2(8x-4)-(2(3x+2)+x)=0
We multiply parentheses
-3x+16x-(2(3x+2)+x)-8=0
We calculate terms in parentheses: -(2(3x+2)+x), so:We add all the numbers together, and all the variables
2(3x+2)+x
We add all the numbers together, and all the variables
x+2(3x+2)
We multiply parentheses
x+6x+4
We add all the numbers together, and all the variables
7x+4
Back to the equation:
-(7x+4)
13x-(7x+4)-8=0
We get rid of parentheses
13x-7x-4-8=0
We add all the numbers together, and all the variables
6x-12=0
We move all terms containing x to the left, all other terms to the right
6x=12
x=12/6
x=2
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