-3x+39(4x-5)=21

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Solution for -3x+39(4x-5)=21 equation: 



-3x+39(4x-5)=21

We move all terms to the left:

-3x+39(4x-5)-(21)=0

We multiply parentheses

-3x+156x-195-21=0

We add all the numbers together, and all the variables

153x-216=0

We move all terms containing x to the left, all other terms to the right

153x=216

x=216/153

x=1+7/17

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